1047:判断能否被3,5,7整除
时间:2024-05-28 11:26
作者:lizq
点击:次
#include iostreamusing namespace std;int main(){ int a; cina; if(a%3==0){ cout3" ";}if(a%5==0){cout5" ";}if(a%7==0){cout7" ";}if(a%3!=0a%5!=0a%7!=0){cout'n';} return 0;}
#include <iostream>
using namespace std;
int main(){
int a;
cin>>a;
if(a%3==0){
cout<<3<<" ";
}
if(a%5==0){
cout<<5<<" ";
}
if(a%7==0){
cout<<7<<" ";
}
if(a%3!=0&&a%5!=0&&a%7!=0){
cout<<'n';
}
return 0;
}
(责任编辑:lizq) |