2054:【例3.4】适合晨练
时间:2024-05-28 11:33
作者:lizq
点击:次
#include iostream#include iomanip#include cmathusing namespace std;int main(){double t;cint;if(t=25t=30){cout"ok!";}else {cout"no!";}return 0;}
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main(){
double t;
cin>>t;
if(t>=25&&t<=30){
cout<<"ok!";
}
else {
cout<<"no!";
}
return 0;
}
(责任编辑：lizq) |