1042:奇偶ASCII值判断
时间:2024-05-28 11:29
作者:lizq
点击:次
#include iostream#include iomanip#include cmathusing namespace std;int main(){char c;cinc;if(c%2==1){cout"YES";}else{cout"NO";}return 0;}
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main(){
char c;
cin>>c;
if(c%2==1){
cout<<"YES";
}
else{
cout<<"NO";
}
return 0;
}
(责任编辑:lizq) |